print done 100 times without using any loop, conditional operator or conditional clause

Normally This question asked after a recursion question or after series of loop question. To verify how much you are listening problem statement without in a hurry behind solution,

Here is Much difficult Answer of Interview

#include <stdio.h>
int print_done_without_loop_and_condition(void){
        printf("DONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\n");
        printf("DONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\n");
        printf("DONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\n");
        printf("DONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\n");
        printf("DONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\n");
        printf("DONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\n");
        printf("DONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\n");
        printf("DONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\n");
        printf("DONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\n");
        printf("DONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\nDONE\n");
}

int main(int argc, char *argv[]){
        print_done_without_loop_and_condition();
        return 0;
}

Compile and Output

rajesh@ideapad:~/Rajesh/Blog$ gcc print_done.c
rajesh@ideapad:~/Rajesh/Blog$ ./a.out 
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE
DONE